Lewis structures of hydrogen phosphate HO4P-2
A simple method for writing Lewis structures is given in a previous article entitled “Lewis Structures and the Octet Rule”. Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).
Another example for writing Lewis structures following the above procedure is given in this post.
Let us consider the case of the Lewis electron dot structures of hydrogen phosphate HO4P-2.
Step 1: The central atom will be the P atom since it is the less electronegative. Connect the atoms with single bonds:
Step 2: Calculate the # of electrons in π bonds (multiple bonds) using formula (1) in the article entitled “Lewis Structures and the Octet Rule”.:
Where n in this case is 5, excluding the H atoms. Where V = (6 + 6 + 6 + 6 + 5 + 1) – (-2) = 32 ,
V is the number of valence electrons of HO4P-2. Therefore, P = 6n + 2 – V = 6 * 5 + 2 – 32 = 0
So, there is no multiple bond in the molecule.
Step 3 & 4: The resonance structures of HO4P-2 are as follows:
Please see the following video that shows step-by-step how to use this method to draw Lewis structures:
Relevant Posts
Simple Method for writing Lewis Electron Dot Structures of the hydrogen phosphate ion (PO3)-1
Simple Method for writing Lewis Structures of the phosphate ion (PO4)-3
References
- G.N. Lewis, J.A.C.S, 38, 762-785, (1916)
- E. C. McGoran, J. Chem. Educ., 68, 19-23 (1991)
- A.B.P. Lever, J. Chem. Educ., 49, 819-821, (1972)
- Steven S. Zumdahl, “Chemical Principles” 6th Edition, Houghton Mifflin Company, 2009
Key Terms
Lewis structures of, simple method for writing Lewis electron dot structures, Lewis electron dot structures, electron dot structures
How come the octet rule is not obeyed in the case of hydrogen phosphate?
ReplyDeleteElements below the second row of the periodic table (third, fourth..) can accommodate more than 8 electrons in the outermost shell. In the above case P has 10 valence electrons. The last Lewis structure in Fig. 2 is more favorable than the one above with 8 valence electrons around P because of less charge separation.
DeletePi electron is zero how did we come up in having 1 multiple bond?
ReplyDelete