There is large
amount of evidence that SN2 reactions proceed with a backside attack
of the nucleophile Nu at the carbon atom attached to the leaving group X1-3.
Fig. 1: Mechanism for the SN2 reaction
|
In a previous
post entitled “The SN2 reaction: Substitution Nucleophilic
Bimolecular” the kinetic evidence for the SN2 mechanism was shown.
However, much
more convincing evidence is obtained from the fact that the mechanism of
the SN2 reaction predicts
inversion of configuration when substitution occurs at a chiral carbon. This
inversion of configuration that proceeds through transition state 1 (Fig. 1) is
called Walden inversion.
Walden presented
a number of examples in which inversion must have taken place such as the one
shown in Fig. 2
Fig. 2: Inversion of configuration is observed when
(+)-malic acid is treated with PCl5 while retention of configuration
when treated with SOCl2
|
When (+)-malic acid reacts with PCl5 the substitution
reaction (OH is replaced by Cl) proceeds with inversion of configuration and
(-)-chlorosuccinic acid is produced – an SN2 reaction occurs. When
(+)-malic acid reacts with SOCl2 the substitution reaction proceeds
with retention of configuration – an SN1 type of mechanism is
involved.
At that point of time Walden was not able to explain the above
findings in terms of reaction mechanisms.
In 1923, Phillips and coworkers carried out a series of experiments in order to prove where inversion takes place. The following experiment was carried out. (+)-1-phenyl-2-propanol was converted to its ethyl ether by the two routes shown in Fig. 3. Path AB gave the (-) ether while path CD gave the (+) ether. Therefore, at least one of the four steps must be an inversion. It is extremely unlikely that there is inversion in steps A, C, D since in all these steps the C-O bond is unbroken. Therefore, only in step B inversion occurred.
In 1923, Phillips and coworkers carried out a series of experiments in order to prove where inversion takes place. The following experiment was carried out. (+)-1-phenyl-2-propanol was converted to its ethyl ether by the two routes shown in Fig. 3. Path AB gave the (-) ether while path CD gave the (+) ether. Therefore, at least one of the four steps must be an inversion. It is extremely unlikely that there is inversion in steps A, C, D since in all these steps the C-O bond is unbroken. Therefore, only in step B inversion occurred.
A number of such experiments were carried out and they showed that
certain specific reactions proceed with inversion.
For example, when (+)-(S)-sec-butanol is treated with TsCl/pyridine
followed by Bu4N AcO/DMF – SN2 reaction conditions –
inversion is observed at the chiral carbon where the substitution takes place.
However, when the same alcohol is treated with SOClF/SbF5 and H2O
– SN1 reaction conditions – a racemic mixture is obtained (Fig. 4)
Fig. 3: Inversion of configuration is observed when (+)-1-phenyl-2-propanol is treated with TsCl and K2CO3
/ EtOH
|
Fig. 4: The SN2 reaction goes with
inversion of configuration at the carbon atom under attack but the SN1 reaction gives a racemic
product.
|
Another kind of evidence for the SN2 mechanism comes from
compounds with leaving groups at bridgehead carbons4 (Fig.
5). These compounds do not react with ethoxide ion – under SN2 conditions
- while their open-chain analogs react readily. However, this is what it is
expected for bridge-head carbons since there is no possibility for the
nucleophile to approach from the rear.
Another evidence for the SN2 mechanism comes from the
fact that as the carbon atom under attack becomes substituted with bulkier
groups the approach for the nucleophile is more difficult due to steric
hindrance and as a result SN2 reactions do not occur. As a matter of
fact the reactivity of carbon atoms, attached to a potential leaving group,
towards SN2 reactions follow the order shown in Fig. 6
Another example of steric hindrance on SN2 reactions is shown in Fig. 7. The reaction is SN2 and 2-chloropropane reacts with hydrogen carbide even though it is a secondary halide while 1-chloro-2,2-dimethylpropane - a primary halide - does not react. This is due to the difficulty that the nucleophile has to approach the carbon atom due to the bulky substituent group attached.
References
1. L. Sun et al., J.A.C.S., 123, 5753 (2001)
2. R. Bruckner, “Advanced Organic Chemistry – Reaction Mechanisms”,
2nd Edition, Elsevier, 2002
3. M.B. Smith & J. March “March’s Advanced Organic Chemistry”, 6th
Edition, Wiley-Interscience, 2007
4. P. Muller, J.
Mareda in G.A. Olah “Cage Hydrocarbons”, Wiley, 1990
No comments:
Post a Comment