A

**simple procedure**for writing**Lewis structures**is given in a previous article entitled “Lewis Structures and the Octet Rule”.**Relevant worked examples**were given in the following articles: Examples #1, #2, #3 , #4, #5, #6, #7, #8, #9, #10, #11, #12, #13, #14, #15, #16, #17, #18, #19, #20, #21, #22, #23, #24, #25, #26 and #27.Let us consider the case of diphosphene P

_{2}H

_{2}

_{ }

__Step 1__: Connect the atoms with single bonds.

Fig. 1: Connecting the atoms of P _{2}H_{2} with single bonds |

__Step 2__: Calculate the # of electrons in π bonds (multiple bonds) using

**formula (1)**:

Where n in this
case is 2 since P

_{2}H_{2}consists of 4 atoms but two of them are hydro gen.
Where V = (1 + 5
+ 5 + 1 ) = 12

Therefore, P = 6n
+ 2 – V = 6 *2 + 2 – 12 = 2

**So there is one double bond and therefore****the structure in Step 1 has one double bond.**__Step 3 & 4__: The

**Lewis structure**of P

_{2}H

_{2}is as follows:

Figure 2: Lewis structure for diphosphene, P _{2}H_{4} |

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