A simple procedure for writing Lewis electron structures is given in a previous
article entitled “Lewis
Structures and the Octet Rule”.
Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).
Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).
Let us consider the case of diazenium ion, N2H3+.
Step 1: Connect the atoms with single bonds. The central atom is the nitrogen atom.
Fig. 1: Connect the atoms of the diazenium ion N2H3+ with single bonds. |
Step 2: Calculate the # of electrons in π bonds (multiple bonds) using formula (1):
Where n in this
case is 5 since N2H3+ consists of 5 atoms.
Where V = (5 + 5
+1 + 1 + 1 ) -1 = 12
Therefore, P = 6n
+ 2 – V = 6 *2 + 2 – 12 = 2 Therefore, there is one double bond in the
structure in Step 1.
Step 3 & 4: The Lewis
structure for N2H3+
is as follows:
Figure 2: Lewis structure for diazenium ion |
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